SOLUTION: How many liters of a 20% alcohol solution and a 10% alcohol solution should be mixed to obtain 50 liters of a 12% alcohol solution?

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Question 73047: How many liters of a 20% alcohol solution and a 10% alcohol solution should be mixed to obtain 50 liters of a 12% alcohol solution?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x=number of liters of 20% solution, y=# of liters of 10% solution
If we want 50 liters of the combined sum of the 2 solutions it will look like this
x%2By=50
Since we want 50 liters of 12% solution it comes to
50%2A0.12=6
And to mix the solutions we use the equation (for instance 30% of 10 liters + 20% of 10 liters = 5 liters, this is an example not the answer)
0.2x%2B0.1y=6
Now use the linear solver to get our answer
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cx+%2B+1%5Cy+=+50%2C%0D%0A++++0.2%5Cx+%2B+0.1%5Cy+=+6+%29%0D%0A++

Any system of equations:


has solution

or



(x=10, y=40}

So we want 10 liters of 20% solution and 40 liters of 10% solution