SOLUTION: If two cars start from 92 miles apart and travel directly towards each other, and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles per hour faster, and they
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Question 730328: If two cars start from 92 miles apart and travel directly towards each other, and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles per hour faster, and they meet up at noon, what is the average speed of each car? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! If two cars start from 92 miles apart and travel directly towards each other,
and one car starts at 11Am and the other starts at 11:15AM and goes 6 miles
per hour faster, and they meet up at noon, what is the average speed of each car?
:
Let s = speed of the Car1
then
(s+6) = speed of Car2
;
The travel time of each car from the information given
Car 1: 1 hr, Car 2: 45 min or .75 hr
:
Write a distance equation: dist = time * speed
:
Car 1 dist + Car 2 dist = 92 mi
1s + .75(s+6) = 92
s + .75s + 4.5 = 92
1.75s = 92 - 4.5
s =
s = 50 mph is the speed of Car 1
then, obviously
56 mph is the speed of car 2
:
:
:
Check this by finding the actual distance each car went
1*50 = 50 mi
.75*56 = 42 mi
----------------
total dist: 92 mi
