SOLUTION: Berlyium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 2400g of berlyium-11 to decompose into 75g of berlyium-11?
Thats the question, and
Algebra ->
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-> SOLUTION: Berlyium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 2400g of berlyium-11 to decompose into 75g of berlyium-11?
Thats the question, and
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Question 730115: Berlyium-11 decomposes into boron-11 with a half life of 13.8 seconds. How long will it take 2400g of berlyium-11 to decompose into 75g of berlyium-11?
Thats the question, and I tried solving it but im stuck. This is what I have so far:
75=2400 x 2^-t/13.8
0.01325=27.6 (-t) Found 2 solutions by lynnlo, ikleyn:Answer by lynnlo(4176) (Show Source):
You can put this solution on YOUR website! .
Beryllium-11 decomposes into boron-11 with a half life of 13.8 seconds.
How long will it take 2400g of beryllium-11 to decompose into 75g of berlyium-11?
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First, from chemical and physical points of views, your post was written terrifically.
I mean the name of Beryllium. So I re-wrote it in correct form.
Next, this problem is very special and very specific.
For the complete solution, there is NO NEED to write many-store complicated exponential functions.
There is a special method and a special approach/reasoning, and this problem
is SPECIALLY CREATED for you to learn this special solution method from me.
Notice that the ratio is 32.
It means that 5 (five) half-lives happened in this decay process
from 2400 gram of Beryllium-11 to 75 grams of Beryllium-11, because = 32.
5 half-lives is 5 times 13.8 seconds, or 5 * 13.8 = 69 seconds.
ANSWER. It will take 69 seconds for 2400 grams of Beryllium-11 to decompose to 75 grams of Beryllium-11.
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