SOLUTION: At a fund raising service in a church,there were twice as more women as there were men.The men paid $7.5 each and the women paid $5 each.The total cash collected was $3850.How many

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: At a fund raising service in a church,there were twice as more women as there were men.The men paid $7.5 each and the women paid $5 each.The total cash collected was $3850.How many      Log On


   



Question 729988: At a fund raising service in a church,there were twice as more women as there were men.The men paid $7.5 each and the women paid $5 each.The total cash collected was $3850.How many people were in the church that day?
Found 3 solutions by lynnlo, ikleyn, timofer:
Answer by lynnlo(4176) About Me  (Show Source):
Answer by ikleyn(53751) About Me  (Show Source):
You can put this solution on YOUR website!
.
At a fund raising service in a church, there were twice as more women as there were men.
The men paid $7.5 each and the women paid $5 each. The total cash collected was $3850.
How many people were in the church that day?
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        This problem ideally suits to be solved mentally.


In accordance with the problem, we can group men and women in the church in sets,
each containing two women and one men each.


Every such group contributes 2*5 + 7.5 = 17.5 dollars into the total 3850 dollars.


Hence, the number of such groups is  3850/17.5 = 220.


It gives 220 men and 2*220 = 440 women, or 220 + 440 = 660 persons, in total.    ANSWER

Solved.

You can do algebra in the same way - it will lead you to the same answer.



Answer by timofer(155) About Me  (Show Source):
You can put this solution on YOUR website!
Something seems wrong with the wording. If you mean twice as many women as men, then could use
men, x
women, 2x
total participants, 3x


7.5x%2B5%282x%29=3850
17.5x=3850
x=220

You want three times that, so 660 people gave in the fund raiser.