SOLUTION: jacob is twice as old as sue.the sum of their ages is 69 years.how old is jacob?

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Question 729947: jacob is twice as old as sue.the sum of their ages is 69 years.how old is jacob?
Answer by Leaf W.(135) About Me  (Show Source):
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Sue's age = x
Jacob's age = 2*(Sue's age) = 2x
.
Jacob's age + Sue's age = 69
2x + x = 69
3x = 69
x = 23
.
Sue's age (x) is 23 years old. Since Jacob's age is twice this, it is 2*23 = 46 years old. Therefore, Jacob is 46 years old.