SOLUTION: The length of a rectangle is 3 feet less than twice the width. The perimeter of the rectangle is 54 square feet. Find the dimensions of the rectangle. (LW=A)

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Question 729895:
The length of a rectangle is 3 feet less than twice the width. The perimeter of the rectangle is 54 square feet. Find the dimensions of the rectangle. (LW=A)
Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
P=2L+2W
L=2W-3
54=2(2W-3)+2W
54=4W-6+2W
6W=54+6
6W=60
W=50/6
W=10 ANS. FOR THE WIDTH.
L=2*10-3
L=20-3=17 ANS. FOR THE LENGTH.
PROOF:
54=2*17+2*10
54=34+20
54=54