SOLUTION: THE DIAMETER OF THE WHEEL OF A CAR IS 5OCM.THE CAR TRAVELLS 72KM/HR,THEN WHAT IS THE DISTANCE COVERED BY CAR IN 1SEC,AND HOW MANY TIMES THE WHEEL RPTATES WITHIN 1 SECOND??
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-> SOLUTION: THE DIAMETER OF THE WHEEL OF A CAR IS 5OCM.THE CAR TRAVELLS 72KM/HR,THEN WHAT IS THE DISTANCE COVERED BY CAR IN 1SEC,AND HOW MANY TIMES THE WHEEL RPTATES WITHIN 1 SECOND??
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Question 729826: THE DIAMETER OF THE WHEEL OF A CAR IS 5OCM.THE CAR TRAVELLS 72KM/HR,THEN WHAT IS THE DISTANCE COVERED BY CAR IN 1SEC,AND HOW MANY TIMES THE WHEEL RPTATES WITHIN 1 SECOND?? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! 72 km/h = (72000/3600) m/s
= 20 m/s
it travels 20 m in 1 sec
=2000 cm
circumference of wheel = pi *d
=3.14*50
=157 cm
Number of rotations = 2000/157
= 12.74 rev