SOLUTION: Find Three consecutive odd integers such that twice the product of the second and third is 1 more than the opposite of the first.

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Question 729758: Find Three consecutive odd integers such that twice the product of the second and third is 1 more than the opposite of the first.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: (x-2), x, (x+2)

2(x)(x+2) = 1 - (x-2)
2x^2 + 4x = -x + 3
2x^2 + 5x - 3 = 0
(x + 3)(2x - 1) = 0
x = -3, x = 1/2

x is an integer, so the integers are -5, -3, -1.