SOLUTION: there are 2. got them wrong on a test and cant come up with the teachers answer 1) solve for X: a/bx-c=0 . I get x=cb/a 2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squa

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: there are 2. got them wrong on a test and cant come up with the teachers answer 1) solve for X: a/bx-c=0 . I get x=cb/a 2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squa      Log On


   

Question 729748: there are 2. got them wrong on a test and cant come up with the teachers answer
1) solve for X: a/bx-c=0 . I get x=cb/a
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
1) solve for X: a/bx-c=0 . I get x=cb/a
Is it (a/b)x ?
Or a/(bx) ?
2) subtract: 3x+1/x2(squared)-9 minus 2x-2/x2(squared -9. my answer x-1/x2(squared -9
Use ^ (Shift ^) for exponents.

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

1) solve for X:
a%2Fbx-c=0
a%2Fbx=c
a=cbx
a%2Fcb=x........answer


2) %283x%2B1%29%2F%28x%5E2-9%29+-+%282x-2%29%2F%28x%5E2+-9%29...if denominator same, just subtract numerators
%28%283x%2B1%29+-+%282x-2%29%29%2F%28x%5E2+-9%29

%283x%2B1-2x%2B2%29%2F%28x%5E2+-9%29

%28x%2B3%29%2F%28x%5E2+-3%5E2%29.....factor denominator

%28x%2B3%29%2F%28%28x+-3%29%28x%2B3%29%29

cross%28%28x%2B3%29%291%2F%28%28x+-3%29cross%28%28x%2B3%29%29%29

1%2F%28x+-3%29