SOLUTION: I was wondering if you could help me find the solution set for this problem. I am not sure of how to find the solution set either.
x^4-6x^3-3x^2+24x-4=0
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-> SOLUTION: I was wondering if you could help me find the solution set for this problem. I am not sure of how to find the solution set either.
x^4-6x^3-3x^2+24x-4=0
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Question 729726: I was wondering if you could help me find the solution set for this problem. I am not sure of how to find the solution set either.
x^4-6x^3-3x^2+24x-4=0 Answer by josgarithmetic(39620) (Show Source):
You can put this solution on YOUR website! Better if you know how to do synthetic division, but you can still use polynomial division to find binomial factors according to Rational Roots Theorem. There are a few choices to try for binomial factors, but the successful ones will be (x-2) and (x+2). You will be able to factor the polynomial into this equation:
. The roots (or zeros) are +2, -2, 3+2*2^(1/2),
and 3-2*2^(1/2). The non-factorable quadratic factor has irrational roots.
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