SOLUTION: Find the exact solution to the equation 3^x+5 = 9^x. HELP Pleeze

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Question 72952: Find the exact solution to the equation 3^x+5 = 9^x.
HELP Pleeze

Answer by bucky(2189) About Me  (Show Source):
You can put this solution on YOUR website!
Interesting problem.
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Given:
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3%5Ex%2B5+=+9%5Ex Find x.
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Recognize that 9%5Ex is equal to %283%2A3%29%5Ex which in turn is equal to %283%5Ex%29%2A%283%5Ex%29
and this is equal to %283%5Ex%29%5E2. Lots of practice using the power rule for exponents
in that little exercise. Anyway, substitute %283%5Ex%29%5E2 for 9%5Ex in the original
equation you were given. When you do the equation becomes:
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3%5Ex%2B5+=+%283%5Ex%29%5E2
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Off to the races! So we can find it a little easier to see what's going on, let's define
z as being equal to 3%5Ex. Go through the equation and substitute z everywhere
you see 3%5Ex. When you do that the equation becomes:
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z+%2B+5+=+z%5E2
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Subtract z%5E2 from both sides of the equation to get:
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-z%5E2+%2B+z+%2B+5+=+0
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Then multiply the whole thing by -1 to get the standard quadratic form of:
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z%5E2+-+z+-+5+=+0
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Compare this to the standard quadratic form of ax%5E2+%2B+bx+%2B+c+=+0 and you see that
a = 1, b = -1, and c = -5. Substitute these values into a solution for the quadratic form
which is (since we are actually solving for z):
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z+=+-b%2F%282%2Aa%29+%2B+%28sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F%282%2Aa%29
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substitute the values for a, b, and c to get:
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this simplifies to:
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z+=+1%2F2+%2B+sqrt%281+%2B+20%29%2F2+=+1%2F2+%2B+sqrt%2821%29%2F2+
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the extreme right side of this equation is just a number you can whip out on a calculator.
You need to check this but I got z+=+2.791287847.
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But now we need to go back to our definition for z. We said that z+=+3%5Ex%29 and we can
substitute that for z to get 3%5Ex+=+2.791287847
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Let's solve this by taking the log of both sides:
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log%283%5Ex%29+=+log%282.791287847%29
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By the rules of logs, the exponent on the left side becomes the multiplier of the log and
the equation becomes:
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x%2Alog%283%29+=+log%282.791287847%29
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Solve for x by dividing both sides of this equation by log(3) to arrive at:
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x+=+log%282.791287847%29%2Flog%283%29
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The right side of this can be done on a calculator. I got x+=+0.934363372
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If you go back to the original problem and substitute this value for x, you should find
that the left side of the equation 3%5Ex+%2B+5 equals the right side of the equation
9%5Ex. Use a calculator to do this ... obviously.
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Sound OK??? Not so fast. Remember way back when we used the quadratic formula to solve
for z. We only looked at the value of z when there was a plus sign between the -b%2F%282a%29
and the %28sqrt%28b%5E2+-+4%2Aa%2Ac%29%29%2F%282a%29. There is another solution for z when you put a minus
sign between these two terms. This second solution is z+=+1%2F2+-+sqrt%2821%29%2F2+=+-1.791287847.
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Again replace z by 3%5Ex and you get 3%5Ex+=+-1.791287847. As we did previously,
take the log of both sides and you will end up with x+=+log%28-1.791287847%29%2Flog%283%29
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But if you try to take the log of the negative number in the numerator you will get an error
indication. Logs of negative numbers don't work. So we can discard this as a possible answer.
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The answer to your problem x = 0.934363372.
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Wow! Lots of fun with this one. Time for another Pepsi.
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Hope this helps you. Since this was a pretty complex problem, I figured you had a math
background with logs and exponents. I sure hope that you were able to track what I did here.
Good luck ...