SOLUTION: The sum of three consecutive even integers is 408. What is the largest of the three integers?

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Question 729461: The sum of three consecutive even integers is 408. What is the largest of the three integers?
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

If we start with an even number and each number in the sequence is 2 more than the previous number then we will get consecutive+even+integers.
Let x be first even number, than x+%2B+2+ is second and x+%2B+4 third consecutive number.
Their sum is:
x%2B%28x%2B2%29%2B%28x%2B4%29=408...solve for x

x%2Bx%2B2%2Bx%2B4=408
3x%2B6=408
3x=408-6
3x=402
x=402%2F3
x=134.....first even number
x%2B2=136.....second even number
x%2B4=138.....third even number
so,the largest of the three integers is 138

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of three consecutive even integers is 408. What is the largest of the three integers?
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408/3 = 136, the middle number