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Question 729299: Write a slope-intercept equation for a line with the given characteristics.
m = - 3/5, passes through (-4,-1) y = mx + b
I thought it would be y = -3/5(-4) + -1
y = 12/5x + -1
The answer in the book says it's y = -3/5x - 17/5
I don't understand what happened with (-4,-1) or how the y-intercept became 17/5.
The book example only shows a simple m = -4, y-intercept (0,-7) Which I know is Y = -4x - 7.
I didn't take Algebra in high school. (I've been out for a lot of years) College Algebra is required for my degree, and it is draining me. I spend hours watching teachers on you tube.
Thank you for any steps and help you can give me.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Write a slope-intercept equation for a line with the given characteristics.
m = - 3/5, passes through (-4,-1) y = mx + b
I thought it would be y = -3/5(-4) + -1
y = 12/5x + -1
The answer in the book says it's y = -3/5x - 17/5
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Use y = mx + b and the point to find b, the y-intercept
-1 = (-3/5)*-4 + b
b = -17/5
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--> y = (-3/5)x - 17/5
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