SOLUTION: 3. A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that (

Algebra ->  Probability-and-statistics -> SOLUTION: 3. A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that (      Log On


   



Question 729292: 3. A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that

(a) all three of the disks are defective?
(b) none of the three disks are defective?
(c) exactly one of the three disks is defective?
(d) at least one of the three disks works?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A box contains 40 computer disks, 5 of which are defective. Three disks are selected from the box (without replacement and regard to order). What is the probability that
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(a) P(all three of the disks are defective) = 5C3/40C3
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(b) P(none of the three disks are defective) = 35C3/40C3
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(c) P(exactly one of the three disks is defective) = [5*35*34]/[40*39*38]
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(d) P(at least one of the three disks works) = 1 - (answer to b)
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Cheers,
Stan H.