Question 729283: Suppose tanθ=-3/4 and π/2<θ<π. Evaluate the five remaining trigonometric functions of θ.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Suppose tanθ=-3/4 and π/2<θ<π. Evaluate the five remaining trigonometric functions of θ.
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Theat is in QII where x is negative, y is positive, r is always positive.
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Since tan(theta) = y/x = -3/4, y = 3 and x = -4
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Then r = sqrt(3^2 + 4^2] = 5
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sin = y/r = 3/5
cos = x/r = -4/5
tan = -3/4
csc = r/y = 5/3
sec = r/x = -5/4
cot = -4/3
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Cheers,
Stan H.
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