SOLUTION: A radiator contains 6 quarts of a 25% antifreeze solution. How much antifreeze should be drained and replaced with pure antifreeze to yield a 33% solution?
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Question 72902: A radiator contains 6 quarts of a 25% antifreeze solution. How much antifreeze should be drained and replaced with pure antifreeze to yield a 33% solution? Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website! 6*.25+X=.33(X+6)
1.5+X=.33X+1.98
X-.33X=1.98-1.5
.67X=.48
X=.48/.67
X=.7164 QUARTS OF 100% ANTIFREEZE NEEDS TO BE ADDED TO GET TO A 33% MIXTURE.
PROOF
6*.25+.7164=.33(.7164+6)
1.5+.7164=.33*6.7164
2.2164=2.2164
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