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Question 728839: I need help with writing this equation.
The question is "Write the equation of the line through (-3,1) that is parallel to the line whose equation is 2x+y=1."
Please help me on what to do. I do know that I need to re-write equation in slope intercept form, so the equation is y=-2x+1, with a slope of -2. And I know that parallel lines have the same slope. But I don't know what to do from there. Thank you
Answer by mbmodak(32)   (Show Source):
You can put this solution on YOUR website!
The given line 2x+y=1 or 2x+y-1=0
Slope of this line=-coefficient of x/coefficient of y
slope=-2/1=-2
The line passing thr(-3,1) has slope=m=-2
using point-slope form
y-y_1=m(x-x_1) here y_1=1 &x_1=-3
y-1=-2*((x-(-3))
y-1=-2x-6
y+2x+6-1=0 Changing sides
2x+y+5=0 slope of this line=-2 & it passes thr(-3,1) i.e.2*(-3)+1+5=0
2x+y+5=0 is the equation of line parallel & passing thr(-3,1)
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