SOLUTION: Angelina can ride her bicycle at a rate of 15 miles per hour from her house to Darryl's house. From Darryl's house, the two of them ride in his ca to work at 45 miles per hour. If
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Angelina can ride her bicycle at a rate of 15 miles per hour from her house to Darryl's house. From Darryl's house, the two of them ride in his ca to work at 45 miles per hour. If
Log On
Question 72853: Angelina can ride her bicycle at a rate of 15 miles per hour from her house to Darryl's house. From Darryl's house, the two of them ride in his ca to work at 45 miles per hour. If Angelina takes exactly one hour to travel 27 miles from her house to work, how many miles did she ride her bicycle? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Angelina can ride her bicycle at a rate of 15 miles per hour from her house to Darryl's house. From Darryl's house, the two of them ride in his car to work at 45 miles per hour. If Angelina takes exactly one hour to travel 27 miles from her house to work, how many miles did she ride her bicycle?
:
Let x = distance riding the bike:
:
We're told the total distance is 27 mi, therefore:
(27-x) = distance riding in the car
:
We're given the total time for the trip is 1 hr, write a time equation:
Time = Dist/speed
;
Bike time + Car time = 1 hr + = 1
:
Multiply equation by 45, gets rid of the denominators
3x + (27-x) = 45
3x - x + 27 = 45
2x = 45 - 27
2x = 18
x = 9 mi on the bike
:
Check time using Bike dist(9 mi) and car dist(18 mi)
9/15 + 18/ 45 =
3/5 + 2/5 = 1
:
How about this, did it make sense?