SOLUTION: Find the maximum height of h=-16t^2+40t+5

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Question 728491: Find the maximum height of h=-16t^2+40t+5
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the maximum height of h=-16t^2+40t+5
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Vertex occurs where t = -b/(2a) = -40/(2*-16) = 5/4
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Max height = h(5/4) = -16(5/4)^2+40(5/4)+5 = 30
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graph%28400%2C400%2C-10%2C10%2C-10%2C50%2C-16x%5E2%2B40x%2B5%29
Cheers,
Stan H.
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