Question 728460: how many liters of a 30% saline solution must be mixed with a 40% saline solution to obtain 25 liters of a 32% saline solution? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! how many liters of a 30% saline solution must be mixed with a 40% saline solution to obtain 25 liters of a 32% saline solution?
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Let x = amount (liters) of 30%
then
25-x = amount (liters) of 40%
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.30x + .40(25-x) = .32(25)
.30x + 10-.40x = 8
10-.10x = 8
-.10x = -2
x = 20 liters (of 30%)
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amount of 40%:
25-x = 25-20 = 5 liters
