SOLUTION: 1.A coin and a 1-6 number cube are tossed.Find P(heads and a prime number grater than 2) 2.Each letter of word DIVISIBILITY is writen on seperate card and the cards are placed

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Question 72843: 1.A coin and a 1-6 number cube are tossed.Find P(heads and a prime number grater than 2)

2.Each letter of word DIVISIBILITY is writen on seperate card and the cards are placed in a bag.Then two cards are selected randomly without repacing the first card.Find P(letter I, letter I )
3.The sum of Sue's age and Sam's age is 35.The product of their ages is 300.
If Sue is younger than Sam,how old is Sam.
Answer by blfaust(5) (Show Source):
You can put this solution on YOUR website!
1. The probability of heads is one-half Also 3 and 5 are the only primes between 1 and 6 that are greater than 2. So, equals We want the Probability that both are going to happen so we multiply them together...=1/6 There is a one in six chance of this happening.
2. The word "DIVISIBILITY" contains 11 letters and it has five "I's" in it. So the chance of the first card having an "I" is 5/11. Now that one card with an "I" is gone, because P stated you were going to pull an "I" followed by another "I", you only have four "I's" left and ten cards total. 4/10 reduced is 2/5 Multiply them together to find the P of both of them happening. 10/55 reduces to 2/11
3. x+y=35 and x*y=300 Create a chart of numbers that add up to 35. Ex. 34+1...33+2...32+3...down to 18+17. You will see that there are only seventeen pairs of numbers to choose from. Now find a pair that gives you a product of 300. Soon you will see that 20*15+300. Since Sue is younger, Sam is 20.