SOLUTION: 2-log3x = log(x/12) how would you go about solving this problem?

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: 2-log3x = log(x/12) how would you go about solving this problem?      Log On


   

Question 727727: 2-log3x = log(x/12)
how would you go about solving this problem?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
2-log3x = log(x/12)
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2 - [log(3)+log(x)] = log(x)-log(12)
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2 - log(3)-log(x) = log(x) - log(12)
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2 - log(3) = 2log(x) - log(12)
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log(x^2) = 2 - log(3)+log(12)
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log(x^2) = 2 + log(12/3)
log(x^2) = 2.6021
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x^2 = 10*2.6021
x = 1.4537
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Cheers,
Stan H.