SOLUTION: I would appreciate your help with these three equations. 1. 5/c = 1/c 2. 0.6 = 1/m 3. -9=1/k I have c = 6/5 for the first, m= 60 for the second and k =-1/9 for t

Algebra ->  College  -> Linear Algebra -> SOLUTION: I would appreciate your help with these three equations. 1. 5/c = 1/c 2. 0.6 = 1/m 3. -9=1/k I have c = 6/5 for the first, m= 60 for the second and k =-1/9 for t      Log On


   



Question 727634: I would appreciate your help with these three equations.

1. 5/c = 1/c
2. 0.6 = 1/m
3. -9=1/k
I have c = 6/5 for the first, m= 60 for the second and k =-1/9 for the third.
thank you so much

Answer by checkley79(3341) About Me  (Show Source):
You can put this solution on YOUR website!
1. 5/c = 1/c cross multiply
5c=1c
5=1 not a valid equation.
2. 0.6 = 1/m cross multiply.
0.6m=1
m=1/0.6
m=1 2/3 ans.
3. -9=1/k cross multiply.
-9k=1
k=1/-9
k=-1/9 ans.