SOLUTION: solve for x and y using substitution or addition method 8x+7y=-4 7x-9y=4

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Question 727292: solve for x and y using substitution or addition method
8x+7y=-4
7x-9y=4

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition


Lets start with the given system of linear equations

8%2Ax%2B7%2Ay=-4
7%2Ax-9%2Ay=4

In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).

So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.

So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 8 and 7 to some equal number, we could try to get them to the LCM.

Since the LCM of 8 and 7 is 56, we need to multiply both sides of the top equation by 7 and multiply both sides of the bottom equation by -8 like this:

7%2A%288%2Ax%2B7%2Ay%29=%28-4%29%2A7 Multiply the top equation (both sides) by 7
-8%2A%287%2Ax-9%2Ay%29=%284%29%2A-8 Multiply the bottom equation (both sides) by -8


So after multiplying we get this:
56%2Ax%2B49%2Ay=-28
-56%2Ax%2B72%2Ay=-32

Notice how 56 and -56 add to zero (ie 56%2B-56=0)


Now add the equations together. In order to add 2 equations, group like terms and combine them
%2856%2Ax-56%2Ax%29%2B%2849%2Ay%2B72%2Ay%29=-28-32

%2856-56%29%2Ax%2B%2849%2B72%29y=-28-32

cross%2856%2B-56%29%2Ax%2B%2849%2B72%29%2Ay=-28-32 Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.



So after adding and canceling out the x terms we're left with:

121%2Ay=-60

y=-60%2F121 Divide both sides by 121 to solve for y



y=-60%2F121 Reduce


Now plug this answer into the top equation 8%2Ax%2B7%2Ay=-4 to solve for x

8%2Ax%2B7%28-60%2F121%29=-4 Plug in y=-60%2F121


8%2Ax-420%2F121=-4 Multiply



8%2Ax-420%2F121=-4 Reduce



8%2Ax=-4%2B420%2F121 Subtract -420%2F121 from both sides

8%2Ax=-484%2F121%2B420%2F121 Make -4 into a fraction with a denominator of 121

8%2Ax=-64%2F121 Combine the terms on the right side

cross%28%281%2F8%29%288%29%29%2Ax=%28-64%2F121%29%281%2F8%29 Multiply both sides by 1%2F8. This will cancel out 8 on the left side.


x=-8%2F121 Multiply the terms on the right side


So our answer is

x=-8%2F121, y=-60%2F121

which also looks like

(-8%2F121, -60%2F121)

Notice if we graph the equations (if you need help with graphing, check out this solver)

8%2Ax%2B7%2Ay=-4
7%2Ax-9%2Ay=4

we get



graph of 8%2Ax%2B7%2Ay=-4 (red) 7%2Ax-9%2Ay=4 (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).


and we can see that the two equations intersect at (-8%2F121,-60%2F121). This verifies our answer.