SOLUTION: How do you use synthetic division to find which value of k will guarantee that the given binomial is a factor of the polynomial? Here is a problem x^3-kx^2-6x+8;x+2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How do you use synthetic division to find which value of k will guarantee that the given binomial is a factor of the polynomial? Here is a problem x^3-kx^2-6x+8;x+2      Log On


   



Question 727283: How do you use synthetic division to find which value of k will guarantee that the given binomial is a factor of the polynomial? Here is a problem
x^3-kx^2-6x+8;x+2

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
You literally perform long division on the polynomials. Divide the x%5E3-kx%5E2-6x%2B8 by x%2B2. Watch each step extremely carefully. In the last subtraction, if you did you algorithm correctly, you should have something equivalent to 8-2%282k-2%29=12-4k, and THIS MUST EQUAL ZERO, if the divisor, x%2B2 is to be a binomial factor of the dividend cubic polynomial. Set 12-4k=0 and find k=3.