Question 727251: The point (3, y) is equidistant from the point (10, 3) and (-5, -1). Find the value of y.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! The point (3, y) is equidistant from the point (10, 3) and (-5, -1). Find the value of y.
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From (3,y) to (10,3):
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From (3,y) to (-5,-1):
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From (3,y) to (10,3):
8y = -7
y = -7/8
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Another approach:
Find the perpedicular bisector of the line between the 2 points, then find y when x = 3.
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