SOLUTION: A catapult is designed to launch extreme circus performers to ridiculous heights from a raised platform. After launch, the height of the performer in feet is given by h(t)=-16t^2+8
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Question 727017: A catapult is designed to launch extreme circus performers to ridiculous heights from a raised platform. After launch, the height of the performer in feet is given by h(t)=-16t^2+80t+32. Where t is seconds after the launch. After how many seconds is the performer 100 feet above the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A catapult is designed to launch extreme circus performers to ridiculous heights from a raised platform. After launch, the height of the performer in feet is given by h(t)=-16t^2+80t+32. Where t is seconds after the launch. After how many seconds is the performer 100 feet above the ground?
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h(t)=-16t^2+80t+32
-16t^2+80t+32 = 100
Solve for t
There are 2 solutions, going up & coming down.
