SOLUTION: Find three consecutive odd integers that the product of the least and greatest is 16 more that the middle integer

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Question 726913: Find three consecutive odd integers that the product of the least and greatest is 16 more that the middle integer
Answer by fcabanski(1391) About Me  (Show Source):
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Call the integers x, x+2 and x+4 (the difference between consecutive odd integers is always 2.)


x is the least, and x+4 is the greatest, and their product is x(x+4) = x%5E2+%2B+4x


That product is 16 more than the middle integer, x+2 or it = x+2+16


x%5E2+%2B+4x+=+x%2B18


x%5E2+%2B+3x+-18+=0


(x+6)(x-3) = 0 so x=-6 and x=3


-6 is even, so x=3 and the integers are 3, 5, and 7

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