SOLUTION: Marcus has a 77 coins, consisting of nickels and dimes, worth $6.10 How many of each kind does he have?

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Question 726766: Marcus has a 77 coins, consisting of nickels and dimes, worth $6.10 How many of each kind does he have?
Answer by tanjo3(60) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be the number of nickels.
Then (77-x) is the number of dimes.
0.05x+%2B+%280.1%29%2877-x%29+=+6.1
0.05x+%2B+7.7+-+0.1x+=+6.1
0.05x+%2B+7.7+-+0.1x+=+6.1
-0.05x+=+-1.6
x+=+32
∴ Marcus has 32 nickels and (77-32=45) dimes.