Question 726764: 2x^2+30x+52
Answer by DrBeeee(684)   (Show Source):
You can put this solution on YOUR website! Factor
(1) 2x^2 +30x + 52 = 0
Always look for a common factor of ALL terms in the equation, then remove it to make the coefficients smaller and easier to work with. In (1), 2 is a common factor. Remove it leaves us with
(2) x^2 + 15x + 26 = 0, which readily factors into
(3) (x + 13)*(x + 2) = 0, which gives the roots
(4) x = {-13,-2}
Let's check these value using (1).
Is (2*(-13)^2 +30*(-13) + 52 = 0)?
Is (2*(169) -390 + 52 = 0)?
Is (338 -390 + 52 = 0)?
Is (-52 + 52 = 0)?
Is (0 = 0)? Yes
Is (2*(-2)^2 +30*(-2) + 52 = 0)?
Is (2*4 -60 + 52 = 0)?
Is (8 -60 + 52 = 0)?
Is (-52 + 52 = 0)?
Is (0 = 0)? Yes
Answer: The solution for x = {-13,-2}
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