SOLUTION: Ok so I need to know how to solve this with work shown for class.
Pipe a and b can together fill a swimming pool in 2 hours. If only pipe a is used, the pool can be filled in 3
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Ok so I need to know how to solve this with work shown for class.
Pipe a and b can together fill a swimming pool in 2 hours. If only pipe a is used, the pool can be filled in 3
Log On
Question 726724: Ok so I need to know how to solve this with work shown for class.
Pipe a and b can together fill a swimming pool in 2 hours. If only pipe a is used, the pool can be filled in 3 hours. How long would it take for only pipe b to fill the pool?
Could you show the work and explain to me how you got the answer? Answer by mananth(16946) (Show Source):
You can put this solution on YOUR website! Filling the pool is 1 job
Pipe A + pipe B takes 2 hours
So they will do 1 / 2 of the job in 1 hour
Pipe A alone takes 3 hours
It does 1 / 3 of the job in 1 hour
If Pipe A does the job in x hours it does 1/x of the job in 1hour
1 / 2 - 1 / 3 = 1/x
LCD = 6
( 3 - 2 ) / 6 = 1/x
1 / 6 = 1/x
Cross multiply
1 x = 6
x= 6 hours
