SOLUTION: Factor completely {{{(y-1)^4-(y-1)^2}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Factor completely {{{(y-1)^4-(y-1)^2}}}      Log On


   

Question 726670: Factor completely
%28y-1%29%5E4-%28y-1%29%5E2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
(y-1)^4-(y-1)^2
This is a difference of 2 squares
[(y-1)^2+(y-1)][(y-1)^2-(y-1)]
(y^2-2y+1+y-1)(y^2-2y+1-y+1)
(y^2-y)(y^2-3y+2)
y(y-1)(y-2)(y-1)