SOLUTION: Find an equation of the circle that has center (1,-5) and passes through (5,-1)

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Question 726637: Find an equation of the circle that has center (1,-5) and passes through (5,-1)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of the circle that has center (1,-5) and passes through (5,-1)
Standard form of equation for a circle: %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2, (h,k)=(x,y) coordinates of center, r=radius
Use distance formula to find radius:
radius=√[(x1-x2)^2+(y1-y2)^2]=√[(5-1)^2+(-1+5)^2]=√[(4)^2+(4)^2]=√32=4√2
radius^2=32
Equation for given circle: %28x-1%29%5E2%2B%28y%2B5%29%5E2=32