SOLUTION: find 3 consecutive odd integers such that the product of the first and third ones is 7 more than 10 times the middle one
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Question 726517
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find 3 consecutive odd integers such that the product of the first and third ones is 7 more than 10 times the middle one
Answer by
CubeyThePenguin(3113)
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consecutive odd integers: (x-2), x, (x+2)
(x-2)(x+2) = 7 + 10x
x^2 - 4 = 7 + 10x
x^2 - 10x - 11 = 0
(x - 11)(x + 1) = 0
x = 11, x = -1
sets of integers: (9, 11, 13), (-1, 1, 3)