SOLUTION: find 3 consecutive odd numbers whose sum is 5 more than twice the next consecutive odd number

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Question 726305: find 3 consecutive odd numbers whose sum is 5 more than twice the next consecutive odd number

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

If x is any odd number, then x and x+%2B+2 are consecutive odd numbers.
you need four consecutive odd numbers, and they are:x,x+%2B+2, x+%2B+4, and x+%2B+6
given:
3 consecutive odd numbers whose sum is 5 more than twice the next (fourth) consecutive odd number
so, you have
x%2B%28x+%2B+2%29%2B%28x+%2B+4%29=2%28x+%2B+6%29%2B5
x%2Bx+%2B+2%2Bx+%2B+4=2x+%2B+12%2B5
3x+%2B+6=2x+%2B+17
3x-2x=17-6
x=11......first odd number
x%2B2=13.....second odd number
x%2B4=15.....third odd number
and
x%2B6=17.....fourth odd number