You can
put this solution on YOUR website! Solve and show work.
The length of a rectangle is 2 cm more
than twice its width. If the perimeter
of the rectangle is 52 cm, find the
dimensions of the rectangle.
Translate "The length of a rectangle is
2 cm more than twice its width" as
"Write down twice the width, 2w, and then
add 2 to make it 2 cm more, getting
2w + 2". So LENGTH = 2w+2
Draw a rectangle and place w
on the widths and 2w+2 on the lengths:
___________________
| 2w+2 |
w| |w
| |
|___________________|
2w+2
Perimeter means add all the sides all the way around
the rectangle:
Perimeter = Left side + Top side + Right side + Bottom side
52 = w + 2w+2 + w + 2w+2
52 = w + 2w + 2 + w + 2w + 2
Solve that and get w = 8
Now find the length by substituting in
LENGTH = 2w+2
LENGTH = 2(8) + 2 = 16+2 = 18
So the length = 18 cm and the width is 8 cm.
Edwin
