SOLUTION: When interest is compounded continuously, the balance in an account after t years is given by P(t)=PO^e^kt, where PO is the initial investment and k is the interest rate. Suppose t

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: When interest is compounded continuously, the balance in an account after t years is given by P(t)=PO^e^kt, where PO is the initial investment and k is the interest rate. Suppose t      Log On


   



Question 726265: When interest is compounded continuously, the balance in an account after t years is given by P(t)=PO^e^kt, where PO is the initial investment and k is the interest rate. Suppose that PO is invested in a savings account where interest is compounded continuously at 8% per year. Express P(t) in terms of PO and 0.08
Answer by stanbon(75887) About Me  (Show Source):
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Suppose that PO is invested in a savings account where interest is compounded continuously at 8% per year. Express P(t) in terms of PO and 0.08
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P(t) = Po*e^(0.08t)
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Cheers,
Stan H.