SOLUTION: Find the equation of the tangent line to the function at the given point f(x) x^2-2x-3 (-2,5)

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Question 726257: Find the equation of the tangent line to the function at the given point
f(x) x^2-2x-3 (-2,5)
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the tangent line to the function at the given point
f(x)= x^2-2x-3 (-2,5)
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slope = f'(x) = 2x-2
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slope at x = -2 = 2*-2-2 = -6
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Form of tangent line equation:
y = mx + b
Solve for "b"
5 = -6*-2 + b
b = -7
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Equation:
y = -6x-7
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Cheers,
Stan H.
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