SOLUTION: The length of a certain rectangle is 15cm more than three times its width. If the perimeter of the rectangle is 94cm, what is the area?

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Question 726135: The length of a certain rectangle is 15cm more than three times its width. If the perimeter of the rectangle is 94cm, what is the area?
Answer by MathLover1(20850) About Me  (Show Source):
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The length of a certain rectangle is L 15cm more than three+times its width W.
+L=3W%2B15cm.....eq.1
If the perimeter P of the rectangle is 94cm,

P=94cm
what is the area A
we know that P=2L%2B2W, ...substitute L from eq. 1 and use given value for P
94cm=2%283W%2B15cm%29%2B2W...solve for W

94cm=6W%2B30cm%2B2W

94cm=8W%2B30cm
94cm-30cm=8W
64cm=8W
64cm%2F8=W
highlight%288cm=W%29
now find L
+L=3W%2B15cm.....eq.1
+L=3%2A8cm%2B15cm
+L=24cm%2B15cm
+highlight%28L=39cm%29
now we can find the area A
A=L%2AW
A=39cm%2A8cm
highlight%28A=312cm%5E2%29