SOLUTION: The foci and ellipse : (x-3)^2/36+(y+2)^2/25=1

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Question 726075: The foci and ellipse : (x-3)^2/36+(y+2)^2/25=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
The foci and ellipse :
(x-3)^2/36+(y+2)^2/25=1
This is an equation of an ellipse with horizontal major axis.
Its standard form: %28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1, a>b, (h,k)=(x,y) coordinates of center
For given equation:
center:(3,-2)
a^2=36
b^2=25
c^2=a^2-b^2=36-25=11
c=√11≈3.3 (center to foci)
foci: (3±c,-2)=(3±3.3,-2)=(-.3,-2) and (6.3,-2)