SOLUTION:
A train departs at noon travelling at a speed of 64km/hr. A car lives the same station half an hour later to over take the train traveling on a road parallel to the track.
If th
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A train departs at noon travelling at a speed of 64km/hr. A car lives the same station half an hour later to over take the train traveling on a road parallel to the track.
If th
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Question 726029:
A train departs at noon travelling at a speed of 64km/hr. A car lives the same station half an hour later to over take the train traveling on a road parallel to the track.
If the cars speed is 96km/hr at what time and at what distance from the station will it over take the train?
i would realy appreciate if i am given detailed solutions because i am having a big problem with world problems Answer by checkley79(3341) (Show Source):
You can put this solution on YOUR website! D=RT
D=64T FOR THE TRAIN.
D=96(T-.5)
64T=96(T-.5)
64T=96T-48
64T-96T=-48
-32T=-48
T=-48/-32
T=1.5 OR AT 1 HOUR 30 MIN. THEY WILL MEET.
D=64*1.5=96 MILES IS THE DISTANCE FROM THE STATION THEY WILL MEET.
PROOF:
96=96(1.5-.5)
96=96*1
96=96
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