SOLUTION: Find three consecutive even integers such that the sum of the least integer and middle integer is 46 more than the greatest integer.
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Question 725911
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Find three consecutive even integers such that the sum of the least integer and middle integer is 46 more than the greatest integer.
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
(x-2) + x = (x+2) + 46
2x - 2 = x + 48
x = 50
The integers are 48, 50, and 52.