SOLUTION: at a fast food restaurant, a family bought 4 hamburgers and 3 bags of french fries for $4.20. At the same time, a family traveling with them bought 5 hamburgers and 2 bags of fren

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Question 725888: at a fast food restaurant, a family bought 4 hamburgers and 3 bags of french fries for $4.20. At the same time, a family traveling with them bought 5 hamburgers and 2 bags of french fries for $4.55. What was the cost of one hamburger and cost of 1 bag of fries
Found 2 solutions by lwsshak3, sfischer18:
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
at a fast food restaurant, a family bought 4 hamburgers and 3 bags of french fries for $4.20. At the same time, a family traveling with them bought 5 hamburgers and 2 bags of french fries for $4.55. What was the cost of one hamburger and cost of 1 bag of fries
**
let x=cost of one hamburger
let y=cost of one bag of fries
..
4x+3y=4.20
5x+2y=4.55
..
8x+6y=8.40
15x+6y=13.65
subtract
-7x=-5.25
x=.75
..
3y=4.20-4x
3y=1.20
y=.40
cost of one hamburger=$.75
cost of one bag of fries=$.40

Answer by sfischer18(2) About Me  (Show Source):
You can put this solution on YOUR website!
let x=cost of one hamburger
let y=cost of one bag of fries
..
4x+3y=4.20
5x+2y=4.55
..
8x+6y=8.40
15x+6y=13.65
subtract
-7x=-5.25
x=.75
..
3y=4.20-4x
3y=1.20
y=.40
cost of one hamburger=$.75
cost of one bag of fries=$.40