SOLUTION: The measures of the angles of a triangle are 3x, 2x-10, and x+40 degrees. Find the number of degrees in the difference between the measures of largest and smallest angles.
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-> SOLUTION: The measures of the angles of a triangle are 3x, 2x-10, and x+40 degrees. Find the number of degrees in the difference between the measures of largest and smallest angles.
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Question 72576: The measures of the angles of a triangle are 3x, 2x-10, and x+40 degrees. Find the number of degrees in the difference between the measures of largest and smallest angles.
I tried:
2x-10=0
2x=10
x=10/2
x=5
And after that I replaced x by 5. My answer is 3*5=15, (2*5)-10=0, and 5+40=45.
Then, the difference between 45 an 0 is 45°
You can put this solution on YOUR website! The sum of the 3 angles equal 180 thus:
3x+2x-10+x+40=180 no combine the x values and the numbers thus:
6x=180-40+10
6x=150
x=150/6
x=25 thus the angles are:
3*25=75
2*25-10=50-10=40
25+40=65
thus the smallest angle is 40
the largest is 75
so the difference is
75-40=35
proof
75+40+65=180
180=180
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