SOLUTION: f(x)=3x^3+x^2-82x+120; -6 is a zero of f(x)

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Question 725759: f(x)=3x^3+x^2-82x+120; -6 is a zero of f(x)
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
f(x)=3x^3+x^2-82x+120; -6 is a zero of f(x)
divide f(x) by -6, using synthetic division
....-6...|.......3........1........82........120
..........................-18......102.....-120
...................3.....-17.......20.........0
f(x)=(x+6)(3x^2-17x+20)
f(x)=(x+6)(3x-5)(x-4)
zeros: -6, 5/3, 4