SOLUTION: Factor if possible 5x^2-20x-xy+4y thanks

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Question 725381: Factor if possible
5x^2-20x-xy+4y
thanks

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
The greatest common factor (GCF) us 1 (which we rarely bother factoring out). There are too many terms for factoring patterns or for trinomial factoring. So we'll try factoring by grouping.

Since factoring by grouping requires grouping (obviously) and sometime reordering the terms, I like to rewrite the expression as additions so that I can do both freely:
5x%5E2%2B%28-20x%29%2B%28-xy%29%2B4y
Now we group the expression into two halves:
%285x%5E2%2B%28-20x%29%29%2B%28%28-xy%29%2B4y%29
Then we factor out the GCF of each group. Two important notes:
  • This point in factoring by grouping is one of those rare times when we actually do factor out a GCF of 1!
  • If the first terms of the two groups have opposite signs, then factor out the negative of the GCF from one of the groups.
The GCF of the first group is 5x. The GCF of the second group is y. But since the first term of the two groups have different signs, we will factor out -y from the second group:
5x%28x%2B%28-4%29%29%2B%28-y%29%28x%2B%28-4%29%29
If we're lucky, the two "non-GCF" factors of the two groups will match. With (x+(-4)) in both groups we got lucky. (If we didn't get lucky then we would have to start over, try a different order and different grouping and repeat this until we get lucky or we figure out that factoring by grouping will just not work.) Factoring out the common factor of (x+(-4)) we get:
%28x%2B%28-4%29%29%285x%2B%28-y%29%29
which should be an acceptable answer. Or you could change back to subtractions:
%28x-4%29%285x-y%29