SOLUTION: y=3/5x^2+30x=282 in vertex form

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Question 725333: y=3/5x^2+30x=282 in vertex form
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
y=3/5x^2+30x=282 in vertex form
complete the square:
y=3/5(x^2+50x+625)=282+375
y=(3/5)(x+25)^2-657
This is an equation of a parabola that opens upward:
Its standard (vertex) form: y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex