SOLUTION: Steve’s canoe goes 14km/hr in still water. He paddled for 2 hours with the current to reach a waterfront bar. Beverly paddled during the return trip against the current and it took

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Question 725213: Steve’s canoe goes 14km/hr in still water. He paddled for 2 hours with the current to reach a waterfront bar. Beverly paddled during the return trip against the current and it took 5 hours to get back to where they started. Find the speed of the current.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +c+ = the speed of the current in km/hr
going against the current the canoe's speed is
+14+-+c+ km/hr
going with the current the canoe's speed is
+14+%2B+c+ km/hr
Let +d+ = the one-way distance the canoe travels
-------------
With the current:
+d+=+%28+14+%2B+c+%29%2A2+
Against the current:
+d+=+%28+14+-+c+%29%2A5+
------------------
By substitution:
+%28+14+%2B+c+%29%2A2+=+%28+14+-+c+%29%2A5+
+28+%2B+2c+=+70+-+5c+
+7c+=+42+
+c+=+6+ km/hr
check:
+d+=+%28+14+%2B+6+%29%2A2+
+d+=+40+ km
and
+d+=+%28+14+-+6+%29%2A5+
+d+=+40+ km
OK