SOLUTION: factor completely. x2-x-35

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Question 725162: factor completely. x2-x-35
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B-1x%2B-35+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%28-1%29%5E2-4%2A1%2A-35=141.

Discriminant d=141 is greater than zero. That means that there are two solutions: +x%5B12%5D+=+%28--1%2B-sqrt%28+141+%29%29%2F2%5Ca.

x%5B1%5D+=+%28-%28-1%29%2Bsqrt%28+141+%29%29%2F2%5C1+=+6.43717104351896
x%5B2%5D+=+%28-%28-1%29-sqrt%28+141+%29%29%2F2%5C1+=+-5.43717104351896

Quadratic expression 1x%5E2%2B-1x%2B-35 can be factored:
1x%5E2%2B-1x%2B-35+=+1%28x-6.43717104351896%29%2A%28x--5.43717104351896%29
Again, the answer is: 6.43717104351896, -5.43717104351896. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-1%2Ax%2B-35+%29