Question 72485This question is from textbook Intermediate Algebra
: Find the equation in standard form, with all interger coefficients, of the line perpendicular to x - 5y = 4 and passing through (-3,5).
This question is from textbook Intermediate Algebra
Found 2 solutions by stanbon, styxillusion:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the equation in standard form, with ll interger coefficients, of the line perpendicular to x - 5y = 4 and passing through (-3,5).
The given line may be written as y=(1/5)x-(4/5), so it has a slope of 1/5.
A perpendicular line must have a slope of -5.
The equation you want is y=mx+b where y=5 when x=-3, and m=-5
Solve for "b".
5=(1/5)(-3)+b
b=25/15/3+3/5
b=28/5
EQUATION:
y=-5x+28/5
Convert to standard form:
Multiply thru by 5 to get:
5y=-25x+28
Rearrange to get the form ax+by=c
25x+5y=28
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Cheers,
Stan H.
Answer by styxillusion(1) (Show Source):
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